3x^2+200x-10000=0

Solution for 3x^2+200x-10000=0 equation:

3x^2+200x-10000=0

a = 3; b = 200; c = -10000;
Δ = b2-4ac
Δ = 2002-4·3·(-10000)
Δ = 160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{160000}=400$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-400}{2*3}=\frac{-600}{6}
=-100
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+400}{2*3}=\frac{200}{6}
=33+1/3
$